Packaging and storage
Preserve in well-filled, tight containers, and avoid exposure to excessive heat.
The label states the Latin binomial and, following the official name, the part of the plant source from which the article was derived. Label it to also indicate whether it is California-type or Italian-type Lemon Oil. The label indicates that Oil is not to be used if it has a terebinthine odor.
Angular rotation 781A:
Transfer about 250 mg of Oil, accurately weighed, to a 100-mL volumetric flask, add alcohol to volume, and mix. Record the UV absorption spectrum of this solution from 260 to 400 nm in a 1-cm cell, using alcohol as the blank. Determine the absorbance at the wavelength of maximum absorbance at about 315 nm using the line drawn tangent to the curves appearing as minima in the spectrum in wavelength regions above and below the maximum wavelength as the baseline. The absorbance, calculated on the basis of a 250-mg specimen, is not less than 0.20 for California-type Lemon Oil, or not less than 0.49 for Italian-type Lemon Oil.
Place 50 mL of Oil in a four-bulb Ladenburg flask having the following dimensions: the lower or main bulb is about 6 cm in diameter, and the smaller condensing bulbs are about 3.5, 3.0, and 2.5 cm in diameter; the distance from the bottom of the flask to the side-arm is about 20 cm. Distill Oil at a rate of 1 drop per second until the distillate measures 5 mL: the angular rotation of the first 5 mL is not more than 6
less than that of the original Oil. The refractive index at 20
of this same portion is between 0.001 and 0.003 lower than that of the original Oil.
Dissolve 4.5 g of hydroxylamine hydrochloride in 13 mL of water, add 85 mL of tertiary butyl alcohol, mix, and adjust with 0.5 N potassium hydroxide to a pH of 3.4. Pipet 50 mL of this solution into a conical flask containing about 5 mL of Oil, accurately weighed. Insert the stopper in the flask, and allow to stand at room temperature for 30 minutes, with occasional shaking. Titrate the liberated hydrochloric acid with 0.5 N alcoholic potassium hydroxide VS to a pH of 3.4. Each mL of 0.5 N alcoholic potassium hydroxide consumed in the titration is equivalent to 76.12 mg, of total aldehydes, calculated as citral (C10H16O).